Python Standard Library

The re Module

“Some people, when confronted with a problem, think ‘I know, I’ll use regular expressions.’ Now they have two problems.”

—Jamie Zawinski, on comp.lang.emacs

The re module provides a set of powerful regular expression facilities, which allows you to quickly check whether a given string matches a given pattern (using the match function), or contains such a pattern (using the search function). A regular expression is a string pattern written in a compact (and quite cryptic) syntax.

The match function attempts to match a pattern against the beginning of the given string, as shown in Example 1-54. If the pattern matches anything at all (including an empty string, if the pattern allows that!), match returns a match object. The group method can be used to find out what matched.

Example 1-54. Using the re Module to Match Strings

File: re-example-1.py

import re

text = "The Attila the Hun Show"

# a single character
m = re.match(".", text)
if m: print repr("."), "=>", repr(m.group(0))

# any string of characters
m = re.match(".*", text)
if m: print repr(".*"), "=>", repr(m.group(0))

# a string of letters (at least one)
m = re.match("\w+", text)
if m: print repr("\w+"), "=>", repr(m.group(0))

# a string of digits
m = re.match("\d+", text)
if m: print repr("\d+"), "=>", repr(m.group(0))

'.' => 'T'
'.*' => 'The Attila the Hun Show'
'\\w+' => 'The'

You can use parentheses to mark regions in the pattern. If the pattern matched, the group method can be used to extract the contents of these regions, as shown in Example 1-55. group(1) returns the contents of the first group, group(2) returns the contents of the second, and so on. If you pass several group numbers to the group function, it returns a tuple.

Example 1-55. Using the re Module to Extract Matching Substrings

File: re-example-2.py

import re

text ="10/15/99"

m = re.match("(\d{2})/(\d{2})/(\d{2,4})", text)
if m:
    print m.group(1, 2, 3)

('10', '15', '99')

The search function searches for the pattern inside the string, as shown in Example 1-56. It basically tries the pattern at every possible character position, starting from the left, and returns a match object as soon it has found a match. If the pattern doesn’t match anywhere, it returns None.

Example 1-56. Using the re Module to Search for Substrings

File: re-example-3.py

import re

text = "Example 3: There is 1 date 10/25/95 in here!"

m = re.search("(\d{1,2})/(\d{1,2})/(\d{2,4})", text)

print m.group(1), m.group(2), m.group(3)

month, day, year = m.group(1, 2, 3)
print month, day, year

date = m.group(0)
print date

10 25 95
10 25 95
10/25/95

The sub function used in Example 1-57 can be used to replace patterns with another string.

Example 1-57. Using the re Module to Replace Substrings

File: re-example-4.py

import re

text = "you're no fun anymore..."

# literal replace (string.replace is faster)
print re.sub("fun", "entertaining", text)

# collapse all non-letter sequences to a single dash
print re.sub("[^\w]+", "-", text)

# convert all words to beeps
print re.sub("\S+", "-BEEP-", text)

you're no entertaining anymore...
you-re-no-fun-anymore-
-BEEP- -BEEP- -BEEP- -BEEP-

You can also use sub to replace patterns via a callback function. Example 1-58 shows how to precompile patterns.

Example 1-58. Using the re Module to Replace Substrings via the callback Function

File: re-example-5.py

import re
import string

text = "a line of text\\012another line of text\\012etc..."

def octal(match):
    # replace octal code with corresponding ASCII character
    return chr(string.atoi(match.group(1), 8))

octal_pattern = re.compile(r"\\(\d\d\d)")

print text
print octal_pattern.sub(octal, text)

a line of text\012another line of text\012etc...
a line of text
another line of text
etc...

If you don’t compile, the re module caches compiled versions for you, so you usually don’t have to compile regular expressions in small scripts. In Python 1.5.2, the cache holds 20 patterns. In 2.0, the cache size has been increased to 100 patterns.

Finally, Example 1-59 matches a string against a list of patterns. The list of patterns are combined into a single pattern, and precompiled to save time.

Example 1-59. Using the re Module to Match Against One of Many Patterns

File: re-example-6.py

import re, string

def combined_pattern(patterns):
    p = re.compile(
        string.join(map(lambda x: "("+x+")", patterns), "|")
        )
    def fixup(v, m=p.match, r=range(0,len(patterns))):
        try:
            regs = m(v).regs
        except AttributeError:
            return None # no match, so m.regs will fail
        else:
            for i in r:
                if regs[i+1] != (-1, -1):
                    return i
    return fixup

#
# try it out!

patterns = [
    r"\d+",
    r"abc\d{2,4}",
    r"p\w+"
]

p = combined_pattern(patterns)

print p("129391")
print p("abc800")
print p("abc1600")
print p("python")
print p("perl")
print p("tcl")

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1
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