Learning C#

How the Call Stack Works

Examine the output of Example 18-2 carefully. You see the code enter Main(), Func1(), Func2(), and the try block. You never see it exit the try block, though it does exit Func2(), Func1(), and Main(). What happened?

When the exception is thrown, execution halts immediately and is handed to the catch block. It never returns to the original code path. It never gets to the line that prints the exit statement for the try block. The catch block handles the error, and then execution falls through to the code following the catch block.

Because there is a catch block, the stack does not need to unwind. The exception is now handled, there are no more problems, and the program continues. This becomes a bit clearer if you move the try/catch blocks up to Func1(), as Example 18-3 shows.

Example 18-3. Unwinding the stack by one level

using System; namespace ExceptionHandling { class Tester { static void Main() { Console.WriteLine("Enter Main..."); Tester t = new Tester(); t.Run(); Console.WriteLine("Exit Main..."); } public void Run() { Console.WriteLine("Enter Run..."); Func1(); Console.WriteLine("Exit Run..."); } public void Func1() { Console.WriteLine("Enter Func1..."); try { Console.WriteLine("Entering try block..."); Func2(); Console.WriteLine("Exiting try block..."); } catch { Console.WriteLine("Exception caught and handled!"); } Console.WriteLine("Exit Func1..."); } public void Func2() { Console.WriteLine("Enter Func2..."); throw new System.Exception(); Console.WriteLine("Exit ...