CHAPTER 13
CHAPTER 13 SOLUTIONS
13.1 SECTION 13.1
13.1 The mean of the data is 
= [27 + 82 + 115 + 126 + 155 + 161 + 243 + 13(250)]/20 = 207.95. The expected value of a single observation censored at 250 is 
. Setting the two equal and solving produce 
= 657.26.
13.2 The equations to solve are
Taking logarithms yields
The solution of these two equations is 
and 
, and then 
.
13.3 The two equations to solve are
Moving the 1 to the left-hand side and taking logarithms produces
Dividing the ...
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