CHAPTER 2

CHAPTER 2 SOLUTIONS

2.1   SECTION 2.2

2.1   image

2.2 The requested plots follow. The triangular spike at zero in the density function for Model 4 indicates the 0.7 of discrete probability at zero.

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2.3 f′(x) = 4(1 + x2)−3 − 24x2(1 + x2)−4. Setting the derivative equal to zero and multiplying by (1 + x2)4 give the equation 4(1 + x2) − 24x2 = 0. This is equivalent to x2 = 1/5. The only positive solution is the mode of image.

2.4 The survival function can be recovered as

Taking logarithms ...

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