Structural Cross Sections

${\tau }_{\mathit{max}}=\frac{{500\times 10}^3}{0.2218\times {40\times 30}^2}=62.6\mathrm{N}-{\mathrm{mm}}^2$

Results

1. Angle of twist is $0.032\mathrm{rad}$

2. Maximum shear stress is $62.6\mathrm{N}-{\mathrm{mm}}^2$

Determination of Allowable Torque

Problem 5: A solid shaft having its outer diameter of $100\mathrm{mm}$. Maximum shear stress of $80\mathrm{MPa}$ is applied on ...