Using the Address of Operator on References
If you ask a reference for its address, it returns the address of its target. That is the nature of references—they are aliases for the target. Listing 11.2 demonstrates this.
Listing 11.2. Taking the Address of a Reference
1: // Demonstrating the use of References
2: #include <iostream>
3:
4: int main()
5: {
6: int intOne;
7: int &rSomeRef = intOne;
8:
9: intOne = 5;
10: std::cout << "intOne: " << intOne << std::endl;
11: std::cout << "rSomeRef: " << rSomeRef << std::endl;
12:
13: std::cout << "&intOne: " << &intOne << std::endl;
14: std::cout << "&rSomeRef: " << &rSomeRef << std::endl;
15:
16: return 0;
17: }
|
intOne: 5 rSomeRef: 5 &intOne: 0x0012FF7C &rSomeRef: 0x0012FF7C
Once again, rSomeRef ... |
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