Time for action – comparing using maxulp of 2

Let's do the same comparisons as in the previous Time for action section, but specify a maxulp of 2 when necessary:

  1. Determine the machine epsilon with the finfo() function:
    eps = np.finfo(float).eps
    print("EPS", eps)

    The epsilon would be as follows:

    EPS 2.22044604925e-16
    
  2. Do the comparisons as done in the previous Time for action section, but use the assert_array_max_ulp() function with the appropriate maxulp value:
    print("1", np.testing.assert_array_max_ulp(1.0, 1.0 + eps))
    print("2", np.testing.assert_array_max_ulp(1.0, 1 + 2 * eps, maxulp=2))

    The output is as follows:

    1 1.0
    2 2.0
    

What just happened?

We compared the same values as the previous Time for action section, but specified a maxulp of 2 in the ...

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