Let's translate the following code into its high-level equivalent. Use the techniques and the concepts that you have learned so far to solve this challenge:
mov dword ptr [ebp-8], 0 mov dword ptr [ebp-4], 0loc_401014: cmp dword ptr [ebp-4], 4 cmp dword ptr [ebp-4], 4 jge loc_40102E mov eax, [ebp-8] add eax, [ebp-4] mov [ebp-8], eax mov ecx, [ebp-4] add ecx, 1 mov [ebp-4], ecx jmp loc_401014loc_40102E:
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