Passing a Reference of a Method That Takes Parameters
| | people.stream() |
| | .sorted(Person::ageDifference) |
We can replace a lambda expression with a method reference if it directly routes the first parameter as a target of a method call, and the remaining parameters as this method’s arguments. The preceding sample code is equivalent to this:
| | people.stream() |
| | .sorted((person1, person2) -> person1.ageDifference(person2)) |
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