2.5. An Initial Peek at Separable Equations with Initial Conditions

It's a given in the world of differential equations: You're going to run into separable first order differential equations with initial conditions. Having to solve a problem with an initial condition adds another dimension to the problem, as you can see in the following example and practice problems.

NOTE

EXAMPLE

Q. Solve this differential equation:

where

y(0) = 2

A.

  1. Multiply both sides of the equation by y2 to get

  2. Then multiply both sides by dx:

    y2 dy = x4 dx

  3. Integrating both sides gives you

  4. Multiply by 3 (and absorb 3 into the constant c):

  5. Then take the cube root:

  6. Solve for c:

    2 = (c)1/3

  7. Here's your solution:

21. Figure out the answer to this differential equation:

where

y(0) = 3

22. Solve this equation:

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