2.5. An Initial Peek at Separable Equations with Initial Conditions
It's a given in the world of differential equations: You're going to run into separable first order differential equations with initial conditions. Having to solve a problem with an initial condition adds another dimension to the problem, as you can see in the following example and practice problems.
NOTE
EXAMPLE
Q. Solve this differential equation:
where
y(0) = 2
A.
Multiply both sides of the equation by y2 to get
Then multiply both sides by dx:
y2 dy = x4 dx
Integrating both sides gives you
Multiply by 3 (and absorb 3 into the constant c):
Then take the cube root:
Solve for c:
2 = (c)1/3
Here's your solution:
21. Figure out the answer to this differential equation:
where
y(0) = 3
22. Solve this equation:
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