Problem 5
Step 1. The problem statement tells us to use /20.
Step 2. The subnets would be 172.16.0.0, 172.16.16.0, 172.16.32.0, 172.16.48.0, 172.16.64.0, and so on, counting by 16 in the third octet.
Step 4. The first three subnets overlap with existing subnets per the details in Table H-5.
Step 5. 172.16.48.0/20 is the numerically lowest new subnet number that does not overlap with the existing subnets.
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