Problem 2
Step 1. The problem statement tells us to use /23.
Step 2. The subnets would be 172.16.0.0, 172.16.2.0, 172.16.4.0, 172.16.6.0, and so on, counting by 2 in the third octet.
Step 4. The first eight such subnets (through subnet 172.16.14.0/23) overlap with the first existing subnet. The first subnet ID that might not overlap would be 172.16.16.0, then 172.16.18.0, and so on.
Step 5. 172.16.16.0/23 is the numerically lowest new subnet number that does not overlap with the existing subnets.
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