The last operation in the BST that we are going to discuss is removing a node based on a given key. We will create a Remove() operation in C++. There are three possible cases for removing a node from a BST, and they are as follows:
- Removing a leaf (a node that doesn't have any child). In this case, we just need to remove the node. From our preceding BST, we can remove keys 7, 15, 29, and 53 since they are leaves with no nodes.
- Removing a node that has only one child (either a left or right child). In this case, we have to connect the child to the parent of the node. After that, we can remove the target node safely. As an example, if we want to remove node 3, we have to point the Parent pointer of node ...
