The compiler will also take the scope of the function into account when looking for a suitable function. You cannot define a function within a function, but you can provide a function prototype within the scope of a function and the compiler will attempt (if necessary through conversions) to call a function with such a prototype first. Consider this code:
void f(int i) { /*does something*/ } void f(double d) { /*does something*/ } int main() { void f(double d); f(1); return 0; }
In this code, the function f is overloaded with one version that takes an int and the other with a double. Normally, if you call f(1) then the compiler will call the first version of the function. However, in main there is a prototype ...
