8.5. Differential Voltage Gain

Suppose that an input voltage, Vg12 = Vg1 – Vg2, is applied between the inputs. Due to symmetry, the voltage magnitudes at the inputs with respect to ground are Vg1 = Vg12/2 and Vg2 = –Vg12/2, respectively. The noninverting output, Vd2, for this case is, by superposition,

Equation 8.21

The gains for the contributions from Vg1 and Vg2 are (8.19) and (8.20), respectively. This is the case of a pure differential input with resulting gain

Equation 8.22

A similar approach applied to obtain the gain for the output ...

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